A person walks on the building.He slips 1m for every 5m he climbs. If the building is 53m high and he takes 5 seconds to climb 1m. Find the total time taken by him to get on the top of the building.

Answer 1

Since you don't say that each 5m portion is a separate attempt (like walking up stairs), I'll assume that his slippage is continuous as he climbs.

That is, it takes him 5*5=25 seconds to climb 5-1=4 meters.

So, his rate of ascent is 4/25 m/s

It will take him 53/(4/25) = 1325/4 = 331.25 seconds to make the climb.

If the climb has to be broken into discrete chunks of 5m each, then things change some.

Answer 2

(n-1)×25/4=325sec
Where n=53
&4m in25 sec

Answer 3

Answer upper bale ka galat h

Answer 4

5m=25seconds
5-1=4m(as he slips 1m for every5m)
Total height of building=53m
He will ned53/4=13sec(Remainder 1ignored)
25*3=325seconds
So, he needs 325sec to climb the building.

Answer 5

Yes

Answer 6

5m 25sec.