when the rock reaches its peak, its velocity is zero, no matter how fast it started out.
The only force acting on it is gravity, so the acceleration is a constant -32ft/s^2 at all times.
A person throws a rock straight up into the air. At the moment it leaves the person's hand it is going 91 mph. When the rock reaches its peak, how fast is it going and what is the magnitude and direction of its acceleration? Ignore air drag
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