A person stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.69 of the person's regular weight. Calculate the magnitude of the acceleration of the elevator.

Answer 1

m= 0.69

a=mg-g

a=(0.69)(9.80)-9.80

a=-3.038 m/s^2

Acceleration is 3.038 m/s^2 downward

Answer 2

cheese technique

Answer 3

no

Answer 4

A person stand on bathroom scale in motionless elevator. When elevator begins to move the briefly reads

only 0.54 of the person's regular weight. Calculate acceleration of elevator.

Answer 5

Fnet = ma
ma = Fn-Fg
Fn = 0.69Fg = 0.69mg
Fg = mg
ma = 0.69mg - mg
cancel out all m in equation and left with:
a=0.69g-g
a=-.31g=-.31*9.8= -3.04 m/s^2
ANSWER: a = -3.04 m/s^2