A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of 18m/s. The cliff is 52m aboce the water's surface. How long does it take for the stone to fall to the water? With what speed does it strike the water? I got how long it took, but how do i find out the speed? help please:) thanks you for your time!
2 answers
The stone is kicked over the edge of the cliff (i.e. horizontally), with a horizontal speed of 18 m/s which remains constant throughout the journey. The initial vertical speed is zero. Determine v using v^2 - u^2 = 2as for vertical motion (u = 0, a = 9.8 m/s^2 and s = 52m). Final speed is the resultant of v and 18 m/s.
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1 answer