horizontal force=40N
pushing force=40/cos20
work done=40*18 Joules
work done by friction=40*18
no work done by gravity.
A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 18.0 m. She pushes in a direction 20.0° below the horizontal. A 40.0-N frictional force opposes the motion of the cart.
(a) What is the magnitude of the force that the shopper exerts?
(b) Determine the work done by the pushing force.
(c) Determine the work done by the frictional force.
d) Determine the work done by the gravitational force.
1 answer