A person pulls the rope in pulley C by 3 meters and lifts the load by 1 meter using the equation for work , how much work is done by the person on the pulley and by the pulley on the load

Answer 1

To calculate the work done by the person on the pulley and by the pulley on the load, we can use the equation for work:

Work = Force x Distance

First, let's calculate the work done by the person on the pulley:

The person pulls the rope by 3 meters, so the distance (d) = 3m.
The force (F) applied by the person to pull the rope can be calculated by the equation F = ma, where m is the mass of the load and a is the acceleration (gravity).

Let's assume the mass of the load is 10 kg, and the acceleration due to gravity is 9.8 m/s^2.

So, F = 10 kg x 9.8 m/s^2
F = 98 N

Now, calculate the work done by the person:

Work = Force x Distance
Work = 98 N x 3 m
Work = 294 Joules

Therefore, the work done by the person on the pulley is 294 Joules.

Now, let's calculate the work done by the pulley on the load:

The load is lifted by 1 meter, so the distance (d) = 1m.
The force (F) exerted by the pulley on the load can be calculated as the weight of the load:

F = m x g
F = 10 kg x 9.8 m/s^2
F = 98 N

Now, calculate the work done by the pulley on the load:

Work = Force x Distance
Work = 98 N x 1 m
Work = 98 Joules

Therefore, the work done by the pulley on the load is 98 Joules.