at the max height, vy=0
vy=vi-gt set vy to zero, solve for t.
Height? Use that time
hf=hi+vit-1/2 gt^2
use the same equation, hf=hi, solve for t.
hf=-50 and hf=vi*t -1/2 gt^2 solve for time
A person on a 50-meter tall building throws a ball straight up into the air. This ball has an initial velocity of 20 m/s. From this:
1) Find the time it would take to reach the Max Height
2) Find the actual Max Height (In Meters)
3) Find the time it takes to return to the person
4) Find the velocity before it reaches the bottom ground.
1 answer