A person jumps off a diving board 4.6 m above the water's surface into a deep pool. The person's downward motion stops 1.6 m below the surface of the water. Estimate the average deceleration (magnitude) of the person while under the water.

Answer 1

since v = at
and s = 1/2 at^2
v = sqrt(2as)

the velocity increases till s = 4.6, then decreases till s = -1.6

-2*9.8*4.6 + 2*a*1.6 = 0
a = 28.175m/s^2