A person is driving an automobile at 95 km/h and throws a bottle of mass .600 kg straight out the window. a) With what momentum does the bottle hit the roadway sign? b) With what momentum does the bottle hit an oncoming automobile traveling in the opposite direction at 85 km/h? c) With what momentum does the bottle hit an automobile passing and traveling in the same direction at 115 km/h?

1 answer

p=m•v
a) v = 95 km/h = 95000/3600 = 26.4 m/s
p = 0.6 • 26.4 = 15.8 kg•m/s
b) v(combined) = 95 + 85 =
26.4+23.6= 50m/s.
p = 50 • 0.6 = 30kg•m/s
c) v(combined)=115 - 95 = 31.9- 26.4
= 5.5 m/s
p= 0.6•5.5 = 3.3 kg•m/s