A person in a kayak starts paddling, and it accelerates from 0 to 0.568 m/s in a distance of 0.389 m. If the combined mass of the person and the kayak is 79.5 kg, what is the magnitude of the net force acting on the kayak?

Answer 1

average speed = .568/2 = .284 m/s
time = t = .389/.284 = 1.37 seconds

a = change in speed / change in time
= .568/1.37 = .415 m/s^2

F = m a = 79.5*.415 = 33 Newtons