B. First because easy.
The car and the pit both travel with the same horizontal speed component until the pit hits the dust
so
the pit hits right under the window.
Now A
How long to drop one meter?
d = (1/2)a t^2
1 = 4.9 t^2
t = .452 seconds
How far will it go at 18 m/s for .452 seconds?
18*.452 = 8.13 meters
a person in a car traveling at 18meters/s drops a cherry pit out of the window 1meter above the ground.
A. how far horrizontal will the pit hit hit ground from the initial dropping point ?
B. if the car continues to travel at the same speed where will the car be in relation to the cherry pit?
4 answers
thank you so much
You are welcome. Remember whenever you bomb something turn the airplane immediately after releasing the bomb. Otherwise the bomb is likely to hit right under the plane.
Haha ok i will for sure remember that