A person hits a 45-g golf ball. The ball comes down on a tree root and bounces straight up with an initial speed of 14.0 m/s. Determine the height the ball will rise after the bounce
The equation is
height= 1/2 velocity^2 / g
where g is 9.8m/s^2
3 answers
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mgh=1/2mv^2
gh = 1/2v^2
9.81 x h = (0.5)(15.0 m/s)^2
9.81/9.81 x h = 56.25/9.81
h = 5.7
gh = 1/2v^2
9.81 x h = (0.5)(15.0 m/s)^2
9.81/9.81 x h = 56.25/9.81
h = 5.7
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3 answers