find the initial vertical velocity. 6sin35.
then, at the top, the final velocity is zero.
vf^2=vi^2+2gh solve for h. g=-9.8m/s^2
A person has the ability to jump with an initial speed of 6.0 m/s at an angle of 35 degree with the ground.
a. How long will the person be in the air?
b. How far horizontally will the person travel?
1 answer
1 answer