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a person has $4 in nickles, quarters, and dimes. there is a total of 36 coins altogether. the number of quarters is 4 less then the number of dimes. Algerbaicly determine the number of each type of coin using a system of 3 equations with 3 variables.

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a).05N+.10D+.25Q=4
b)N+D+Q=36
Q=D-4
c) D-Q=4

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