A pendulum that on Earth has period 0.52 s is taken to the surface of a large asteroid, where it is measured to have period 1.7 s. What is the value of the gravitational acceleration on the surface of that asteroid?

Question

A pendulum that on Earth has period 0.52 s is taken to the surface of a large asteroid, where it is measured to have period 1.7 s.  What is the value of the gravitational acceleration on the surface of that asteroid?

Elena · Answer

T₁=2π•sqrt{L/g₁} T₂=2π•sqrt{L/g₂} g₂=g₁(T₁/T₂)²