The second plate traveled 82deg
displacement=speed*time
82deg*PIrad/180deg=95rad/sec*time
time= 82*PI/180 / 95=.0150 sec
speed bullet= distance/time=.8m/.0150=53.3m/s
A pellet is fired through two circular plates .8 m apart, both rotating at -95rad/s. The angular displacement of second bullet hole is 82° from the first bullet hole. Calculate the bullet’s speed in m/s.
If someone could help me see where to insert the factors in whichever equation that would be very helpful. I'm stuck!
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