h=gt²/2
t=sqrt(2h/g)
x=v(x) •t =>
v(x) =x/t=x/sqrt(2h/g) =
=8.3/sqrt(2•4.3/9.81)=8.9 m/s
A pelican flying along a horizontal path drops
a fish from a height of 4.3 m. The fish travels
8.3 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s
2
.
Answer in units of m/s
1 answer