d = (1/2) g t^2 = 4.9 t^2
at t = 0, d = 0
at t = 1, d = 4.9
at t = 2, d = 4.9*4
at t = 3, d = 4.9 * 9
so from t = 1 to t = 3
it falls
4.9 (9-1) = 4.9*5
A pebble is dropped from rest from the top of a tall cliff and falls 4.9meters after 1 second has elapsed. How much further does it drop in the next 2 seconds?
1 answer