v = -gt = -9.8*2
100 = 4.9 t^2
t = 4.52 seconds to ground
so
v = -9.8*4.52
A pebble is dropped from an open window 100 meters above the ground.
a) What is the velocity of the pebble after 2 seconds?
b) What is the velocity of the pebble when it hits the ground?
1 answer
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