A pears rolls across a table with a speed of 0,5 m/s and falls off the edge, if it lands 3m from the edge of the table from what height does it fall

Answer 1

I will assume that the "3 m from the edge of the table" is the horizontal distance, so
3 = .5t, where t is the time in seconds
t = 6 seconds

vertical distance = 4.9t^2 = 4.9(36) = 176.4 m
not a very logical answer.

So let's assume the 3 m is the direct line from the edge to where it lands, then
(.5t)^2 + (4.9t^2)^2 = 3
.25t^2 + (4.9t^2)^2 = 3
lt t^2 = x
.25x + 24.01x^2 = 3
2401x^2 + 25x - 300 = 0
x = (-25 ± √2881825)/4802
= .3483 or a negative x
t^2 = .3483 ---> t = .5902

height of table = 4.9(.5902)^2 = 1.71 metres
a more logical answer