a peak is sighted at an angle of 27 degree 45 min. 1000ft nearer its angle of elevation is 31 degree 30 min.find the height of the peak

Answer 1

If the nearer observation point is at distance x, and the peak has height h, then we have

h/x = tan 31°30'
h/(x+1000) = tan 27°45'

Now eliminate x and solve for h.