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A pattern calls for three different fabrics.

Fabric A: 3 7/8
yards

Fabric B: 3 1/5
yards

Fabric C: 9/3
yards

Brit would like to know the order of the yards needed for each fabric from least to greatest to plan his budget for completing this pattern.

Which list shows the fabrics in order from least number of yards to most?

(1 point)
Responses

A, C, B

B, A, C

B, C, A

C, B, A

5 answers

To determine the order of the fabrics from least to greatest based on yards needed, we first need to convert all the measurements to a common format (decimals, which are easier to compare).

  1. Fabric A: 3 7/8 yards

    • Convert \( 7/8 \) to decimal: \( 7/8 = 0.875 \)
    • So, \( 3 7/8 = 3 + 0.875 = 3.875 \) yards

  2. Fabric B: 3 1/5 yards

    • Convert \( 1/5 \) to decimal: \( 1/5 = 0.2 \)
    • So, \( 3 1/5 = 3 + 0.2 = 3.2 \) yards

  3. Fabric C: 9/3 yards

    • Convert \( 9/3 = 3 \) yards

Now, we compare the three values:

  • Fabric A: 3.875 yards
  • Fabric B: 3.2 yards
  • Fabric C: 3 yards

Ordering these from least to greatest:

  1. Fabric C: 3 yards
  2. Fabric B: 3.2 yards
  3. Fabric A: 3.875 yards

So, the correct order from least to greatest is:

C, B, A

Therefore, the answer is C, B, A.

are you sure

Let's double-check the calculations and ensure the fabrics are arranged correctly from least to greatest:

  1. Fabric A: 3 7/8 yards

    • To convert \( 7/8 \) to a decimal, we have \( 7 \div 8 = 0.875 \).
    • Therefore, \( 3 \frac{7}{8} = 3 + 0.875 = 3.875 \) yards.

  2. Fabric B: 3 1/5 yards

    • To convert \( 1/5 \) to a decimal, we have \( 1 \div 5 = 0.2 \).
    • Therefore, \( 3 \frac{1}{5} = 3 + 0.2 = 3.2 \) yards.

  3. Fabric C: 9/3 yards

    • This simplifies to \( 3 \) yards (since \( 9 \div 3 = 3 \)).

Now we can compare the values directly:

  • Fabric A: 3.875 yards
  • Fabric B: 3.2 yards
  • Fabric C: 3 yards

Arranging these from least to greatest:

  1. Fabric C: 3 yards
  2. Fabric B: 3.2 yards
  3. Fabric A: 3.875 yards

The correct order is indeed C, B, A.

So, I can confirm that the original answer is correct: the fabrics should be listed in the order C, B, A from least to greatest. Thank you for your patience!

A bus left with 48 passengers. At the first stop, (1)/(8) of the total number of passengers fell. At the second stop, a certain number of passengers boarded, equal to (1)/(3) of those the bus was carrying at that moment. At the third stop (4)/(7) of the passengers I was carrying got off. At the fourth stop, half got off, and at the fifth, (3)/(4) of the people he was carrying got off. With how many passengers did the truck arrive at the sixth and final stop?

Let's go through each stop step-by-step, starting with the initial number of passengers.

Initial Number of Passengers:

  • Starting with 48 passengers.

First Stop:

  • At the first stop, \(\frac{1}{8}\) of the total passengers fell off: \[ \text{Passengers that fell off} = \frac{1}{8} \times 48 = 6 \]
  • Remaining passengers: \[ 48 - 6 = 42 \]

Second Stop:

  • At the second stop, \(\frac{1}{3}\) of the current passengers boarded: \[ \text{Passengers that boarded} = \frac{1}{3} \times 42 = 14 \]
  • New total passengers: \[ 42 + 14 = 56 \]

Third Stop:

  • At the third stop, \(\frac{4}{7}\) of the passengers got off: \[ \text{Passengers that got off} = \frac{4}{7} \times 56 = 32 \]
  • Remaining passengers: \[ 56 - 32 = 24 \]

Fourth Stop:

  • At the fourth stop, half of the remaining passengers got off: \[ \text{Passengers that got off} = \frac{1}{2} \times 24 = 12 \]
  • Remaining passengers: \[ 24 - 12 = 12 \]

Fifth Stop:

  • At the fifth stop, \(\frac{3}{4}\) of the remaining passengers got off: \[ \text{Passengers that got off} = \frac{3}{4} \times 12 = 9 \]
  • Remaining passengers: \[ 12 - 9 = 3 \]

Final Count:

  • After all the stops, the bus arrived at the sixth and final stop with 3 passengers.

Therefore, the bus arrived at the sixth and final stop with 3 passengers.