To find the surface area of the chocolate pyramid, we need to find the area of the triangular base and the area of the three triangular faces.
The area of the triangular base can be found using the formula for the area of a triangle: A = (1/2)bh, where b is the base length and h is the height of the base. In this case, b = 5 in. and h = 4.3 in. Plugging these values into the formula, we get A = (1/2)(5)(4.3) = 10.75 in^2.
The area of each of the three triangular faces can be found using the formula for the area of a triangle: A = (1/2)sl, where s is the slant height and l is the base length. In this case, s = 6 in. and l = 5 in. Plugging these values into the formula, we get A = (1/2)(6)(5) = 15 in^2.
Since there are three triangular faces, the total area of the three triangular faces is 3(15) = 45 in^2.
Adding the areas of the triangular base and the three triangular faces, we get the surface area of the chocolate pyramid: 10.75 + 45 = 55.75 in^2.
Therefore, the correct answer is 55.75 in.2
A pastry chef is creating a chocolate dessert in the shape of a triangular pyramid. The pyramid has a base of 5 in., the height of the base is 4.3 in., and the slant height is 6 in. Use the correct formula to find the surface area of the chocolate pyramid. (1 point) Responses 47.25 in.2 47.25 in. squared 58.25 in.2 58.25 in. squared 52.25 in.2 52.25 in. squared 55.75 in.2 55.75 in. squared
1 answer
1 answer