A pastry chef is creating a chocolate dessert in the shape of a triangular pyramid. The pyramid has a base of 5 in., the height of the base is 4.3 in., and the slant height is 6 in. Use the correct formula to find the surface area of the chocolate pyramid. (1 point)

Responses

58.25 in.2
58.25 in. squared

52.25 in.2
52.25 in. squared

55.75 in.2
55.75 in. squared

47.25 in.2

1 answer

To find the surface area of the triangular pyramid, we need to calculate the area of each triangular face and then add them together.

First, let's calculate the area of the base triangle. The base of the triangle is 5 in. and the height of the triangle is 4.3 in. The formula for the area of a triangle is (1/2) * base * height.

Area of base triangle = (1/2) * 5 in. * 4.3 in. = 10.75 in.²

Next, let's calculate the area of the lateral faces. Since the slant height is given, we can use the formula for the area of a triangle using the slant height. The formula is (1/2) * base * slant height.

Area of each lateral face triangle = (1/2) * 5 in. * 6 in. = 15 in.²

Since there are four lateral faces in a triangular pyramid, the total area of the lateral faces is 4 * 15 in.² = 60 in.²

Finally, to find the total surface area, we add the area of the base and the area of the lateral faces together.

Total surface area of the chocolate pyramid = Area of base triangle + Total area of lateral faces
= 10.75 in.² + 60 in.²
= 70.75 in.²

Therefore, the correct answer is 70.75 in.²