To find the surface area of the chocolate pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base is given by:
Area of base = (1/2) * base * height
Area of base = (1/2) * 5 * 4.3
Area of base = 10.75 in^2
The area of each triangular face is given by:
Area of triangular face = (1/2) * base * slanted height
Area of triangular face = (1/2) * 5 * 6
Area of triangular face = 15 in^2
Since the pyramid has 4 triangular faces, the total area of the four triangular faces is:
Total area of triangular faces = 4 * 15
Total area of triangular faces = 60 in^2
To find the surface area of the chocolate pyramid, we add the area of the base and the area of the four triangular faces:
Surface area = Area of base + Total area of triangular faces
Surface area = 10.75 + 60
Surface area = 70.75 in^2
Therefore, the correct answer is not listed.
A pastry chef is creating a chocolate dessert in the shape of a triangular pyramid. The pyramid has a base of 5 in., the height of the base is 4.3 in., and the slanted height is 6 in. Use the correct formula to find the surface area of the chocolate pyramid.
A) 55.75 in^2
B) 58.25 in.^2
C) 52.25 in.^2
D) 47.25 in.^2
1 answer
1 answer