Sorry, I forgot to add the second part of the question.
What is the net acceleration of the passenger relative to the dock?
A passenger in a boat approaching a dock attempts to step onto the dock before the boat has been tied up. The passenger, whose mass is 57 kg, accelerated at a rate of 3.2 m/s^2 [forward]. If the mass of the boat is 97 kg, what is the boat's acceleration relative to the passenger? Neglect the horizontal force of the water.
3 answers
1.9m/s2 backwards
57kg x 3.2m/s2 forward = 182.4
182.4/97kg = 1.88 round to two significant figures so
1.9m/s2 backwards
182.4/97kg = 1.88 round to two significant figures so
1.9m/s2 backwards