I will be happy to check your thinking.
On the second part, look at the change in mass PE (m+M)gh=change in spring PE
(m+M)gh=1/2 k(5.6+3.0)^2-1/2 k (5.6^2)
solve for the additional mass m .
you did not include units for k, or distances, so they may need to be changed to be unit consistant.
A particular spring has a force constant of 2.6×103 .
Part A
How much mass would have to be suspended from the vertical spring to stretch it the first 5.6 ?
Express your answer using two significant figures.
How much more mass would have to be suspended from the vertical spring to stretch it the additional 3.0 ?
Express your answer using two significant figures.
1 answer
2 answers