A particular household ammonia solution (d= 0.97g/mL) is 6.8% NH3 by mass.
How many milliliters of this solution should be diluted with water to produce 650 mL of a solution with pH = 11.55?
8 answers
I showed you how to do the other one almost step by step. This one should be done the same way. The only difference is that this one is ammonia and the other was KOH.
ok thank u
umm i tried it,,yet im getting the wrong answer..
this is wht i did:
M1 X V1= M2 X V2
V1 = M2 X V2
----------
M1
= 2.45 X 0.65
------------
0.65
= 259.365 ml
this is wht i did:
M1 X V1= M2 X V2
V1 = M2 X V2
----------
M1
= 2.45 X 0.65
------------
0.65
= 259.365 ml
M1*V1= M2*V2 is ok except you haven't calculated the molarity of the 6.8% solution of NH3. Do that first, then calculate the molarity of the solution you want, then you can use the dilution formula.
I DON'T GET WHATS DONE..
DR.Bob22 - could u please explain this again..thank u
DR.Bob22 - could u please explain this again..thank u
it should be approx 0.6 mL
i'm not too sure if it's right though, let me know
I think it's somewhere between 0.56 mL and 0.62 mL, hope that helps!
3 answers