v = 6.8t - 2.2
avg acceleration is
(v(3)-v(1))/(3-1)
A particles position is described by the function x=3.4t^2 - 2.2t + 2.7 (m). Determine the average acceleration (in m/s^2) for the interval of time t1= 1.0s and t2= 3.0s
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