A particles position (in meters) is given by the equation s(t) = 5x sin (2x), on the interval [-1,4] minutes. What is its instantaneous velocity at t = 0

Answer 1

you did not express s as a function of t
perhaps
s(t)=5 t sin 2t ?
if so
ds/dt = 5 [ 2 t cos 2t + sin 2t ]
at t = 0 that is
5 [ 0+0 ] = 0