A particle's constant acceleration is north at 109 m/s2. At t = 0, its velocity vector is 60.7 m/s east. At what time will the magnitude of the velocity be 114 m/s?

Answer 1

Vy = 109 t
Ve = 60.7

114 = sqrt (109^2t^2 + 60.7^2

12996 = 109^2 t^2 + 60.7^2