A particle with a velocity of 2m / s at t = 0 moves along a straight line with a constant acceleration of 0.2m / s s.find the displacement of the particle in10 second
4 answers
well, every second the velocity increases by 0.2 m/s. So how much is that after 10 seconds?
100.2
How did you get 100.2 ??
a = 2
v = at+c = 2t + c
when t = 0, v = 2
2 = 0 + c
v = 2t + 2
s = t^2 + 2t + k
when t=0 , s = 0 , thus k = 0
s = t^2 + 2t
when t = 10
s = 10^2 + 2(10) = 120
a = 2
v = at+c = 2t + c
when t = 0, v = 2
2 = 0 + c
v = 2t + 2
s = t^2 + 2t + k
when t=0 , s = 0 , thus k = 0
s = t^2 + 2t
when t = 10
s = 10^2 + 2(10) = 120
forget about my solution, I saw that as a = 2
instead of a = .2
so s = .1 t^2 + 2t
at t = 10
s = .1(100) + 2(10) = 30 m
instead of a = .2
so s = .1 t^2 + 2t
at t = 10
s = .1(100) + 2(10) = 30 m