A particle with a charge of -4.50x 10^-10 C and a mass of 6.6x 10^-18 kg is placed between two oppositely charged parallel plates with a voltage of 9.00x 10^5 V. The particle is injected at the negative plate with an initial speed of zero. What is the final speed of the particle just before it strikes the positive plate?

asked by Marie

12 years ago

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1 answer

ΔKE = W (of electric field)
0 – mv^2/2 = qU
v=sqrt (2qU/m)

answered by Elena

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Question

A particle with a charge of -4.50x 10^-10 C and a mass of 6.6x 10^-18 kg is placed between two oppositely charged parallel plates with a voltage of 9.00x 10^5 V. The particle is injected at the negative plate with an initial speed of zero. What is the final speed of the particle just before it strikes the positive plate?

1 answer

ΔKE = W (of electric field)
0 – mv^2/2 = qU
v=sqrt (2qU/m)

Ask a New Question or answer this question.

Elena · Answer

ΔKE = W (of electric field) 0 – mv^2/2 = qU v=sqrt (2qU/m)