A particle with a charge of -3.2 μC and a mass of 4.0 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 58 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.

Where would I start with this question?

1 answer

:You know the final KE of the particle, so it has to equal the energy that went into it: 1/2 kv^2=q(Vb-Va)
Similar Questions
    1. answers icon 1 answer
  1. are these correct . Which particle has a negative charge?A. Alpha particle B. Positron C. Neutron- Correct answer D. Beta
    1. answers icon 1 answer
  2. is this correct . Which particle has a negative charge?A. Alpha particle B. Positron C. Neutron- Correct answer D. Beta particle
    1. answers icon 1 answer
  3. A particle of mass 57 g and charge 70 µC isreleased from rest when it is 34 cm from a second particle of charge −12 µC.
    1. answers icon 0 answers
more similar questions