A particle with a charge of -3.2 μC and a mass of 4.0 x 10-6 kg is released from rest at point A and accelerates toward point B, arriving there with a speed of 58 m/s. The only force acting on the particle is the electric force. What is the potential difference VB - VA between A and B? If VB is greater than VA, then give the answer as a positive number. If VB is less than VA, then give the answer as a negative number.
Where would I start with this question?
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:You know the final KE of the particle, so it has to equal the energy that went into it: 1/2 kv^2=q(Vb-Va)
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