Make a reasonable accurate diagram.
Complete the parallelogram and draw in the resultant, you should be familiar with that.
The obtuse angle of the parallelogram is 105° and the acute angle is 75°
By the cosine law:
|r|^2 = 6^2 + 15^2 - 2(6)(15)cos75°
|r| = 14.6428...
angle made with F:
sin75/r = sinØ/15
sinØ = .98948..
Ø = appr 81.7° <--- angle between F and the resultant
but we want the equilibrant, which has opposite direction but the same magnitude.
I will leave it up to you to find the angle as requested.
Hint: Extend lines and use opposite angles.
After all, all angles are now known
A particle, which remains at rest, is acted on by three forces F, G, and H.
The force F has magnitude 6N and is directed to the right and up, making an angle of 20' with the vertical.
The force G has magnitude 15N and is directed to the right and down, making an angle of 55' with the vertical.
Find the magnitude of the vector H, and the acute angle it makes with the vertical.
1 answer
1 answer