A particle wavelength (λp) of a proton is 10-12m.

What is the velocity of this proton [m/s]?

To achieved the velocity that you just computed, what must have been the potential difference (V) through which the proton was accelerated?

An electron of wavelength 1.74*10-10m strikes an atom of ionized helium (He+). What is the wavelength (m) of the light corresponding to the line in the emission spectrum with the smallest energy transition?

6 answers

a) 3.96148749852*10^5
b) 820
c)....?
Thanks dear but actually I got the two first ones last night and stuck with part c. :(
Anyone for c) please?
what about some brainstorming???do we have to use Rydberg's equation??
What about doing your own work and not trying to cheat?
Please stop spamming.