v = u + a t
s = u t + (1/2) a t^2
10 = u(2)+ + (1/2) a (2)^2
or 10 = 2 u + 2 a
28 = u(4) + (1/2) a (16)
or
28 = 4 u + 8 a
20 = 4 u + 4 a
28 = 4 u + 8 a
---------------
8 = 4 a etc
A particle travelling along a straight line starts with a
velociry ofu metres per second and its speed increases
per second by rl metres. The particle travels 10 metres
in 2 seconds and 28 metres in 4 seconds. Find u and a.
(lf the distance travelled in I seconds is s metres. then
s=ut+1/2at^2
1 answer