A particle starts moving from rest with uniform acceleration.It travels a distance x in first 2 sec and a distance y in the next 2 sec.Then Answer) y=3x

Answer 1

correct.

Answer 2

Let the initial velocity be 0. Then in three seconds it becomes 3m/s and again in next three seconds it becomes 6m/s. We know that acceleration here is 3m/s square. Hence in the first case....... If we put the formula as 2as=v square --u square
We will get 2*3*x=9--0
By solving we would get x=3/2
Similarly for second case...
2as=v square --u square. Here since the initial velocity is 3m/s(as the final velocity in first case is initial here) acceleration is 3m/ square
And final velocity is 6m/s.
By using same formula
2as=v square -u square
2*3*Y=36-9
Y. =(27/6) 9/2
When we compare we get
3/2*3=9/2
Hence 3X=Y