To find the speed of the particle 5.0 s after it enters the region with the electric field, we can use the following steps:
1. First, calculate the force experienced by the particle due to the electric field.
Force (F) = charge (q) * electric field (E)
Given q = -4.0 mC and E = 60 N/C
F = (-4.0 x 10^-3 C) * (60 N/C)
F = -240 x 10^-3 N
2. Next, calculate the acceleration experienced by the particle using Newton's second law.
Force (F) = mass (m) * acceleration (a)
Given m = 50 g = 0.05 kg
a = F / m
a = (-240 x 10^-3 N) / (0.05 kg)
a = -4800 m/s^2
3. Now, we can find the final velocity of the particle after 5.0 s using the formula for uniformly accelerated motion.
v = u + at
Given u = 25 m/s (initial velocity), a = -4800 m/s^2 (acceleration), and t = 5.0 s
v = 25 m/s + (-4800 m/s^2) * (5.0 s)
v = 25 m/s - 24000 m/s
v = -23975 m/s
4. Finally, find the speed of the particle, which is the magnitude of the velocity (since speed is a scalar quantity).
speed = |v|
speed = |-23975 m/s|
speed = 23975 m/s
Therefore, the speed of the particle 5.0 s after entering the region with the electric field is 23975 m/s.
A particle (q-4.0 mC.m-50 g) has a velocity of 25 m/s in the positive x direction when it first enters a region where the electric field is uniform (60 N/C in the positive y direction). What is the speed of the particle 5.0 s after it enters this region?
is simple steps
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