A particle of mass 4 units moves along x axis attracted towards the origin by a force with magnitude 8x. if it is initially at rest at x=10, then the frequency of the particle is

2 answers

since F=ma, a = -8x/4 = -2x

x" + 2x = 0
the general solution to this is
x = c1 sin(√2 t) + c2 cos(√2 t)
so, the frequency is 1/(√2 π)
10