A particle of mass 1kg moving with initial velocity (i+2k)m/s is acted upon by a constant force(i+2j-2k)N,calculate the velocity and distance after 5s.

Answer 1

a = F/1 = i + 2 j -2 k
v = Vi + a t
x = Xi + Vi t + (1/2)a t^2

v at 5 = i+0j+2k + 5i +10j -10k
= 6i + 10j - 8k

x at 5, well assume start at (0,0,0)

x = 0 +(i+0j+2k)5 +(1/2)(i + 2 j -2 k)25

= 5i+0j+10k+(1/2)(25i+50j-50k)
=17.5 i +25 j -15 k

check my arithmetic !