This is an IVP (initial value problem).
x"(t)=(6t-4) ms-2 ....(1)
"...if the particle is at origin and has a velocity of ? when t=0."
Integrate (1) with respect to t to find x'(t) and x(t). Do not forget the integration constants at each integration.
Use the initial conditions
x(0)=0 and x'(0)=(???)
to find C1 and C2 (int. constants).
When C1 and C2 are known, evaluate
x(3) and x'(3) as required.
A particle moves on the x-axis with an acceleration, a=(6t-4)ms⁻1. Find the position and velocity of the particle at t=3 , if the particle is at origin and has a velocity of when t=0
2 answers
thanzz again