A particle moves in the xy-plane, starting from the origin at t = 0 with an initial velocity v0 = (20ˆi – 15ˆj) m/s and a constant acceleration of a = 4.0ˆi m/s2. Determine the particle’s speed and direction at t = 5.0 s.

Answer 1

v(t) = v0 + at
so,
v(5) = <20,-15> + 5<ax,ay>
where ax and ay are the components of the acceleration. Since you don't supply them, it's hard to determine v

Answer 2

ax = 4 and ay = 0