since v(t) = sin (2t)
then s(t) = -(1/2)cos(2t) + c , where s(t) is the distance
when t = 0,
s(0) = -(1/2)cos 0 + c
= c - 1/2
when t = π
s(π) = -(1/2)cos 2π + c
= c - 1/2
distance traveled = s(π) - s(0)
= c - 1/2 - (c - 1/2)
= 0
which is exactly what you would get.
Just a different way of writing it.
A particle moves along the x-axis with velocity v(t) = sin(2t), with t measured in seconds and v(t) measured in feet per second. Find the total distance travelled by the particle from t = 0 to t = π seconds.
Do I have to take the integral of the equation like ∫ sin(2t) where a=0 b=pi
5 answers
whats the answer lol
He specifically says it in the end, learn how to actually ready before making comments like that Pablo lol.
The answer is 0.
The answer is 0.
idk either guys
you don't know the answer then dont say it you nerd