A particle moves along the x-axis so that at any time t≥0, its velocity is given by v(t)=t^2-16t+4 What is the velocity of the particle when its acceleration is zero?

Answer 1

since a(t) = 2t - 16
when a(t) = 0
t = 8

v(8) = 64 - 16(8) + 4 = ......