do you mean
v(t) = 8 t^3 ???
where v is velocity in x direction???
if so
s = s(0) + integral from 0 to t of 8 t^3 dt
= s(0) + 2 t^4
= 5 + 2 t^4
A particle moves along the s-axis. Use the given information to find the position of the particle. v(t)=8t3 ;
s(0) = 5.
4 answers
yes i did mean
v(t) = 8 t^3 in the x direction.
v(t) = 8 t^3 in the x direction.
i have a feeling some thing is wrong in your assumption of the question .. could u please recheck ?
I see Bob Pursley got the same answer I did.