a particle moves along the curve y= sqrt 1+x cubed. As it reaches the point (2,3) the y-corrdinate is increasing at a rate of 4cm/s. How fast is the x-coordinate of the point changing at that instant?

Answer 1

y= sqrt(1+x^3)
dy/dt= 1/2 * 1/sqrt(1+x^3)* 3x^2 dx/dt

dy/dt= 3x^2/2y * dx/dt

dx/dt= 2y dy/dt * 1/3x^2

you are given x, y, dy/dt, solve fod dx/dt.

check my work, I did it in a hurry

Answer 2

hey thanks we are checking it now:)