y = 3x^2 + 1
dy/dt = 6x dx/dt
so,
3 = 6*2 dx/dt
dx/dt = 1/4
A particle moves along the curve y = 3x2 + 1 in such a way that the y value is increasing at the rate of 3 units per second. At what rate is x changing when x = 2?
1 answer