a particle moves according to the law a=1/t √t. if s=8 when t=1. and s=16 when t=4. find v when t=9.
5 answers
do we have a = 1/(t√t) or is it a = (1/t)√t ??
a = 1/(t√t)
ok, then
a = t^(-3/2)
v = -2 t^(-1/2) + c
s = -4 t^(1/2) + ct + k
case1: s=8, when t = 1
8 = -4 + c + k
12 = c + k
case2: s = 16, when t = 4
16 = -4(2) + 4c + k
24 = 4c + k
subtract them:
12 = 3c
c = 4
back in 12 = c+k
12 = 4+k
k = 8
then v = -2/√t + 4
when t = 9
v = -2/3 + 4 = 10/3
a = t^(-3/2)
v = -2 t^(-1/2) + c
s = -4 t^(1/2) + ct + k
case1: s=8, when t = 1
8 = -4 + c + k
12 = c + k
case2: s = 16, when t = 4
16 = -4(2) + 4c + k
24 = 4c + k
subtract them:
12 = 3c
c = 4
back in 12 = c+k
12 = 4+k
k = 8
then v = -2/√t + 4
when t = 9
v = -2/3 + 4 = 10/3
Thank you very, very much. I'm really grateful.
welcome,
hope you checked my arithmetic
hope you checked my arithmetic