A particle is projected at 10ms^-1 from a height of 45m. Calculate the horizontal distance covered by the particle before reaching the ground(g=10ms^-2)

Answer 1

assuming it was projected horizontally, then since distance=speed*time, all you need to do is figure out how long it takes to fall 45m:

4.9t^2 = 45

Answer 2

45=(1/2 )10t*2 solve for t=2 seconds .d=10t=10*2=20m